Question

ABC is a right triangle, right angled at B and AC=200 cm. D, E & F are points on AC such that AD=DE=EF=FC. Then find the value of BD²+BF².​

Answer 1

Answer:

66 is the right answer

Step-by-step explanation:

ok..

Answer 2

Answer:

Step-by-step explanation:

In this question the hypotenus AC in bisected by BE so it forms an angle of 90 at E . and bisection of hypotenus is possible only in issoselus right angled triangle so A = 45 degree . Put tan45 = BE/AE ie 100/BE tan 45 = 1 so BE=100cm now by pythagoras theorem BE^2 + DE^2 = BD^2 . 100^2 +50^= 12500 =BD^2 . triangle BDE is similar triangle BFE ie EF = DE ( given ) angle E = 90 both side and BE common .So by CPCT BD=BF and BD^2 = BF^2 so 12500 + 12500 = 25000cm