ABC is a right triangle, right angled at B. BC = BA.
D is a point on AC produced and a line DEF cuts
CB at E, AB at F. IF ZD = 13º and ZFAE = 29, then
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Step-by-step explanation:
❖Question:-
BC is a right triangle, right angled at B. BC = BA. D is a point on AC produced and a line DEF cuts CB at E, AB at F. IF ZD = 13º and ZFAE = 29, then
❖Solution :-
We are given,
A diagram consists of three triangles ABC ,ACD & ADC - all of them are individually as I isosceles right triangles.
The area of ∆ ABC = 6
You need to determine
The area of ∆ ADE
Approach and working
Let us assume the length of AB = n
As ABC is an isosceles right angle triangle ,AB = BC = n
Therefore, AC = √(n2+2n2) = 2n
we also know that ∆ADE is is an isosceles right angle triangle
hence, AD = DE = 2n
Thus, the area of ∆ADE = 1/2 × 2n × 2n = 2n2
We are also given that area of ∆ABC = 6
.
Hope it helpful .☺
@Somya2563
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