Question

ABC is a right triangle, right angled at B. BC = BA.
D is a point on AC produced and a line DEF cuts
CB at E, AB at F. If angleD = 13° and angleFAE = 29°, then
the measure of FEA is
(a) 31°
(C) 29°
(d) 16°
(b) 42°
​

Answer 1

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$\large \tt \red{✦Answer✦}$

Step-by-step explanation:

❖Question:-

BC is a right triangle, right angled at B. BC = BA. D is a point on AC produced and a line DEF cuts CB at E, AB at F. IF ZD = 13º and ZFAE = 29, then

❖Solution :-

We are given,

A diagram consists of three triangles ABC ,ACD & ADC - all of them are individually as I isosceles right triangles.

The area of ∆ ABC = 6

You need to determine

The area of ∆ ADE

Approach and working

Let us assume the length of AB = n

As ABC is an isosceles right angle triangle ,AB = BC = n

Therefore, AC = √(n2+2n2) = 2n

we also know that ∆ADE is is an isosceles right angle triangle

hence, AD = DE = 2n

Thus, the area of ∆ADE = 1/2 × 2n × 2n = 2n2

We are also given that area of ∆ABC = 6

.

Hope it helpful .☺

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Answer 2

Answer:

We are given,

A diagram consists of three triangles ABC ,ACD & ADC - all of them are individually as I isosceles right triangles.

The area of ∆ ABC = 6

You need to determine

The area of ∆ ADE

Approach and working

Let us assume the length of AB = n

As ABC is an isosceles right angle triangle ,AB = BC = n

Therefore, AC = √(n2+2n2) = 2n

we also know that ∆ADE is is an isosceles right angle triangle

hence, AD = DE = 2n

Thus, the area of ∆ADE = 1/2 × 2n × 2n = 2n2

We are also given that area of ∆ABC = 6

.