Question

ABC is a right triangle right angled at B let B and E be any points on AB and BC respectively prove thatAE²+CD²=AC²+DE² plz as fast as you can

Answer 1

AE^2+CD^2 = AB^2+BE^2      +    BD^2+BC^2= AC^2+  DB^2+BE^2= AC^2+DE^2
LHS=RHS.
HENCE, PROVED