abc is a right triangle right angled at b such that bc=6cm and ab=8cm find the radius of the circle
kvnmurty:
incircle , circumcircle radii
Answers
Answered by
105
Question is about the radius of Incircle or Circumcircle.
ΔABC is a right angle triangle. ∠B = 90°.
AB = 8 cm. BC = 6 cm.
Using Pythagoras theorem we get AC² = AB² + BC² = 100
=> AC = 10 cm
=> Radius of circumcircle = R = 1/2 * Hypotenuse = 5 cm
s = semiperimeter = (a+b+c)/2 = 12 cm
r = incircle radius
Ar(ΔABC) = 1/2 * AB * BC = 24 cm²
= s * r
= 12 * r
=> r = incircle radius = 24/12 = 2 cm.
ΔABC is a right angle triangle. ∠B = 90°.
AB = 8 cm. BC = 6 cm.
Using Pythagoras theorem we get AC² = AB² + BC² = 100
=> AC = 10 cm
=> Radius of circumcircle = R = 1/2 * Hypotenuse = 5 cm
s = semiperimeter = (a+b+c)/2 = 12 cm
r = incircle radius
Ar(ΔABC) = 1/2 * AB * BC = 24 cm²
= s * r
= 12 * r
=> r = incircle radius = 24/12 = 2 cm.
Answered by
32
r of inner circle=24/12 =2cm...
hope it helps....
hope it helps....
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