ABC is a right triangle right angled at B. The charge at B is +8C. Find the
work done to move +2C charge from A to C. AB= 4cm, BC= 3cm.
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Given
BC=6 cm
AB=8 cm
We know that in right angle triangle is AC 2 =AB 2 +BC 2
AC 2 =8 2 +6 2
AC 2 =64+3 AC 2 =100
AC=10 cm
Now
Area of △AN= Area of △OAB+ Area of △OBC+ Area of △OCA
⇒ 21 ×BC×AB= 21 ×r×AB+ 21 ×AC×r+ 21 ×BC×r
⇒ 21 ×6×8=21 ×8×r+ 21 ×10×r+ 21 ×6×r
⇒24r=48
⇒24r=48
⇒r=2 cm
Thus the radius of the circle is 2 cm
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