ABC is a right triangle, right angled at B. The hypotenuse AC is 25 cm and AB : BC =4 : 3. Find the lengths of the sides AB and BC.
The length of side AB =
cm.
The length of side BC
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Answer:
let AB & BC be 4x and 3x respectively,
we have got the length of AC = 25cm
therefore,
In ∆ABC angle B = 90° ,
By Pythagoras theroum,
AC² = AB² + BC²
=> ( 25 )² = ( 4x )² + ( 3x )²
=> 625 = 16x² + 9x² = 25x²
=> x² = 625 = 25
25
=> x = √25 = 5cm
therefore ,
AB = 4x = 4 × 5 = 20cm
BC = 3x = 3 × 5 = 15cm.
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