ABC is a right triangle, right angled at B, with AB = 3 cm and BC = 4 cm. BD is drawn perpendicular to the hypotenuse AC. Find the length of BD if AC = 5 cm
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Answer:
The answer will be BD = 2.4cm.
Step-by-step explanation:
Given things;
∆ABC and ∆ADB are right angled triangle, right angled at B and D respectively.
AB = 3cm
BC = 4cm
AC = 5cm
Now,
In ∆ABC and ∆ADB;
∠ABC = ∠ADB;
∠A = ∠A;
Thus, ∆ABC ~ ∆ADB ( AA criteria of similarity )
Thus, AB/ AD = AC/AB = BC/BD. (i)
Hence, AC/AB = BC/BD. (from eq. (i))
5/3 = 4/BD
BD = 12/5
BD = 12/5
= 2.4cm
That's all.
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