ABC is a right triangle, right angled at C and AB = √2 BC, then find
angle ABC
Answers
Answered by
2
Answer:
angle ABC = 45°
Explanation:
GIVEN :- In triangle ABC
Angle C = 90° & AB =√2BC SO , AB = √ 2 BC
=> AB /√2 = BC
=> 1 / √2 = BC / AB
=> 1 / √2 = COS B { COS B = BC/AB
=> COS 45° = COS B.
{ 1/√2= COS 45° }
=> B = 45 °
Answered by
0
Answer:
angle ABC= 45°
Explanation:
AB = root 2 BC
AB/BC = root 2
ABC is a right angle triangle at C
base/ hypotenuse = root 2
sec @= root 2
=45 °
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