abc is a right triangle right angled at c. If A=30 and AB=40 units, find the remaining two sides and angle B of triangle ABC
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is this question is correct???
Bhagat111:
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sinA = p/h = BC/AB
sin30° = BC/40 unit
1/2 = BC/40 unit
doing cross multiplication,
2BC = 40 unit
BC = 40/2 = 20unit
by Pythagoras theorem,
we get other side
sin30° = BC/40 unit
1/2 = BC/40 unit
doing cross multiplication,
2BC = 40 unit
BC = 40/2 = 20unit
by Pythagoras theorem,
we get other side
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