Question

ABC is a right triangle right angled at C. Let BC = a, CA = b, AB = c and let „p‟ be the length of the perpendicular from C on AB. Prove that (i) cp = ab (ii) 1p2 = 1a2+ 1b2

Answer 1

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Answer 2

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Area of ΔABC=1/2×Base×Height

=> 1/2×BC×AC

=> 1/2 ab

Area of ΔABC=1/2×Base×Height

=> 1/2×AB×CD

=> 1/2 cp

=>1/2 ab = 1/2 cp

=> ab = cp

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