ABC is a right triangle right angled at C. let BC=a,CA=b,AB=c and let p be the length of perpendicular from C on AB. prove that
1. PC=AB
2.1/p^2=1/a^2+1/b^2.
Answers
Answered by
1
Answer:
1.Area is 1/2 base * height . So for the same triangle area can be 1/2*b*a and can be 1/2*p*c. Hence cp = ab
2 . From above p2 = a2b2/c2
1/p2 = c2/ a2b2
but for right triangle c2 = a2 +b2
Hence 1/p2 = (a2+b2)/ a2b2
Hence 1/p2 = 1/a2+1/b2
Similar questions