ABC is a right triangle when angle ABC is 90° and D is the mid point of AC. If AB=1/2 AC. Find angle BDC.
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Answer:
∠BDC = 90°
Step-by-step explanation:
We know that ABC is a right triangle.
∠B = 9
AB = 1/2 AC (given)
=) 2AB = AC...(i)
Here,
AD + DC = AC
=) 2AD = AC...(ii)
From equation (i) and (ii)
AD = AB...(iii)
Now,
∠DBC =1/2* 90° = 45°...(iv)
In triangle ABC,
∠BAC + ∠BCA = 90°
⇒ ∠BCA + ∠BCA = 90°
⇒ 2∠BCA = 90°
⇒ ∠BCA = 45°...(v)
In triangle BCD,
∠DBC = 45°
∠BCD = 45°
So, 45° + 45° + ∠BDC = 180° (angle sum property)
⇒ 90° + ∠BDC = 180°
⇒ ∠BDC = 180° - 90°
⇒ ∠BDC = 90°
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