ABC is a right triangle where ZBAC = 90°. M, P, are points on sides BC, AC
respectively such that MP is the perpendicular bisector of BC, as shown. If AB = 2
cm and MP = (V6 - V2) cm, then CP =
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Construct a triangle ABC in which AB = 5 cm and BC = 4.6 cm and AC = 3.7 cm ... (2) Locate points P and Q on it such that PQ = 5.6 cm. ... Step II: At point B, draw a right angle, say ∠ XBA.
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