Question

ABC is a right triangle with A= 90° and C= 30°. Show that ∆DCA~∆ACB.​

Answer 1

Answer:

Your answer is here:-

Step-by-step explanation:

In ∆DCA and ∆ACB

<D = <A ( 90° )

<C = <C ( common )

<A = <B ( by angle sum property the measure of both the angle is equal )

∆DCA ~ ∆ACB ( by AAA )

Hope it helps you.