. ABC is a right triangle with AB = AC. Bisector of A meets BC at D. Prove that ΔCAD ΔBAD
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(Refer to the attachment for the rough diagram)
To Prove: △CAD ≅ △BAD
Proof:-
In △CAD and △BAD,
- AB = AC (Given)
- ∠CAD = ∠BAD (Bisectors of ∠A)
- AD = AD (Common side)
∴△CAD ≅△BAD by S - A - S congruence criterion.
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