Question

ABC is a right triangle with AB = AC. If bisector of ∠A meets BC at D and AD = 2 2 cm, then the perimeter

of ∆ABC is​

Answer 1

Answer: 4(2+√2)

Here, ∆ADB ≅ ∆ADC

AD = BD = CD = 2√ 2 cm

∴ AB² + AC² = BC² (By Pythagoras theorem)

Step-by-step explanation:

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