ABC is a right triangle with AB=AC. If bisector of angle A meets BC at D and AD = 2√2 cm, then the perimeter of ΔABC is (a) 8 cm (b) 8√2 cm (c) 2(2+√2) cm (d) 4(2+√2) cm
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2(2+√2) is the answer if you like it then mark my answer as a brainliest answer
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