Abc is a traingle at b,with ab=14cm and bc=24cm .With the vertices a,b and c
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Radius of each sector (r) = 7 cm
Let θ1 ,θ2and θ3 be the angles of sectors (angle of triangle)
⇒ θ1+θ2+θ3=180∘(Angle sum-property)
Area of shaded region = Area of ΔAC – Area of 3 sectors
=12×AB×BC−πr2360∘[θ1+θ2+θ3][Area of sector=πr2θ360∘]
=12×14×24−π×7×7360∘×180∘ [AB = 14 cm, BC = 24 cm(given)]
=168−227×7×72
=168−11×7
= 168 – 77
=91 cm2
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