Question

ABC is a Trapezium with AB parallel to DC. M is the midpoint of BC.prove that ar(AMD)=1/2ar(ABCD)

Answer 1

In my solution naming of triangle and midpoint is change but it will be helpful to you. Please see carefully.

Pic have the solution.

Answer 2

Answer:

The Triangle AMDand Trapezium ABCDare on the same base AD and between same parallel AD and BC

So,

area ( triangle AMD ) = 1/2 area ( trapezium ABCD)