ABC is a triangle. A circle touches sides AB an AC produced and side BC at X, Y and Z respectively. Show that AX=1/2 perimeter of ∆ABC
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from the figure u will get that
AX=AY
BX=BZ
CY=CZ
now
per of triangle ABC =ab+bc+ac
=ab+(bz+zc)+ac
=ab+bx+ac+cy
=ax+ay
=2ax
per of triangle ABC =2ax
therefore
1/2perimeter of triangle =ax .
Step-by-step explanation:
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