Question

ABC is a triangle AD is a perpendicular BC=21 AC=14 theta is at B find sec theta​

Answer 1

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

$\frac{1}{2} \times base \times hight$

$= \frac{1}{2} \times AB \times BC$

$= \frac{1}{2} \times 5 \times 12$

$= {30cm}^{3}$

Now, in ΔABC,

Area of triangle ABC=

$= \frac{1}{2} \times </strong><strong>BC</strong><strong> \times </strong><strong>AD</strong><strong>$

$30 = \frac{1}{2} \times 13 \times </strong><strong>AD</strong><strong>$

$= </strong><strong>AD</strong><strong> = \frac{30 \times 2}{13} = \frac{60}{3} cm$