Question

Abc is a triangle and BD And CE are perpendicular to AC and AB respectively. if BD=CE, find the three pairs of corresponding parts which make ΔBCD~=ΔCBE by RHS congruence condition. ​

Answer 1

Step-by-step explanation:

here is your answer

hope, it will help you

Answer 2

Step-by-step explanation:

In triangle ADC & CDE

angle E = angle D

BD = CE (given)

BC = BE(common side)

so triangle BCD congurent to triangle CBE(RHS)