abc is a triangle and d is any point in its interior
show that BD+DC < AB+AC
Question no. 4 in pic
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Answer:
BD + DC < AB + AC
Step-by-step explanation:
Sum of two sides of triangle > Third side
in ΔABE
=> AB + AE > BE
=> AB + AE > BD + DE
in ΔDCE
DE + CE > DC
Adding both
AB + AE + DE + CE > BD + DE + DC
Cancelling DE from both sides
=> AB + AE + CE > BD + DC
AE + CE = AC
=> AB + AC > BD + DC
=> BD + DC < AB + AC
QED
Proved
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1
Step-by-step explanation:
here you go thank you for your response
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