ABC is a triangle and D is the mid-point of BC the perpendiculars from D to AB and AC are equal prove that the triangle is isosceles
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Given :
- ABC is a triangle
- D is the mid point of BC
- the perpendiculars from D to AB and AC are equal. [ ED = DF ]
To be prove :
- the triangle is isosceles
Proof :
In △BED and △DFC
∠BED = ∠DFC = 90°
ED = DF | Given
BD = DC | D is the mid point of
BC
Hence,△ BED ≅ △DFC. | by R.H.S
congruence criteria.
Therefore, ∠ B = ∠ C | by C.P.C.T
Hence, the △ABC is a isosceles triangle.
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