Question

ABC is a triangle and PQ is a line segment parallel to BC which divides the triangle into 2 equal parts find BP:AB ratio

Answer 1

$2 - \sqrt{2 } \div 2$

Answer 2

$\frac{ar(APQ)}{ar(ABC)} = \frac{1}{2}$

$\frac{AP}{AB} = \sqrt{( \frac{1}{2} )}$

$\frac{AP}{AB} = \frac{1}{ \sqrt{2} }$

$\frac{AP}{AB}-1= \frac{1}{ \sqrt{2} } -1$

[tex] \frac{1- \sqrt{2} }{2 } = \frac{-BP}{AB} [/tex]


$\frac{BP}{AB} = \frac{ \sqrt{2}-1 }{2}$