Question

ABC is a triangle and PQ is a straight line meeting AB in P and AC in Q. if AP = 1 cm and BP = 3 cm , AQ = 1.5 cm , prove that area of ∆APQ =1/16 ( area of (∆ABC).​

Answer 1

Step-by-step explanation:

we know that AP/BP =AQ/BQ

squaring both side, we get

AP²/BP²=AQ²/BQ²

let BQ be x

=> 1/9=2.25/x²

=>x²=20.25

=>x=4.5

triangle APQ ~ triangle ABC

APQ/ABC=1²/4²=1/16

HENCE,TRIANGLE APQ=1/16 area of triangle ABC..

hope it may help u.