Question

ABC is a triangle, difference of angle A and B is 15 , difference of angle B and C is 30 ,find the measures of all the angles
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Answer 1

Step-by-step explanation:

B-A = 15

C-B =30

A+B+C =180°

B= A+15

C=B+30

therefore, C= (A+15)+30 = A+ 45

A+ B+C=180°

A +( A+ 15)+( A+45)=180

3A + 60 = 180

3A= 180-60

3A= 120

A= 120/3

A=40°

B= A+15

therefore, B= 40+ 15= 55°

C= A+ 45

therefore, C = 40+ 45 = 85°

check:

40+ 55+85= 180°

Answer 2

Step-by-step explanation:

we might know that A-B = 15 or A = 15 + B are same

and ,

B-C = 30 or C = 30 + B are same

and the sum of all the angles is 180

B/Q,

( 15+B ) + B + ( 30+B ) = 180

=> 3B + 45 = 180

=> 3B = 180 - 45

=> 3B = 135

=> B = 135 ÷ 3

=> B = 45

Now,

B=45

A-B = 15

=>A - 45 = 15

=>A = 15+45

=>A= 60

Again,

B-C = 30

=>

=>45-C = 30

=>C= 30-45

=>C= -15

therefore,

the angles are = A= 60,B=45 and C= -15