ABC is a triangle, difference of angle A and B is 15 , difference of angle B and C is 30 ,find the measures of all the angles
Answers
Answered by
1
Step-by-step explanation:
B-A = 15
C-B =30
A+B+C =180°
B= A+15
C=B+30
therefore, C= (A+15)+30 = A+ 45
A+ B+C=180°
A +( A+ 15)+( A+45)=180
3A + 60 = 180
3A= 180-60
3A= 120
A= 120/3
A=40°
B= A+15
therefore, B= 40+ 15= 55°
C= A+ 45
therefore, C = 40+ 45 = 85°
check:
40+ 55+85= 180°
Answered by
2
Step-by-step explanation:
we might know that A-B = 15 or A = 15 + B are same
and ,
B-C = 30 or C = 30 + B are same
and the sum of all the angles is 180
B/Q,
( 15+B ) + B + ( 30+B ) = 180
=> 3B + 45 = 180
=> 3B = 180 - 45
=> 3B = 135
=> B = 135 ÷ 3
=> B = 45
Now,
B=45
A-B = 15
=>A - 45 = 15
=>A = 15+45
=>A= 60
Again,
B-C = 30
=>
=>45-C = 30
=>C= 30-45
=>C= -15
therefore,
the angles are = A= 60,B=45 and C= -15
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