Question

abc is a triangle i which altitudes bd and ce to sides ac and ab are equal (i) ∆abd is congruent to ∆ace (ii) ab=ac i.e abc is an isosceles triangle
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Answer 1

Answer:

1. send a proper diagram or photo of triangle

Answer 2

Given: ABC  is a triangle in which altitudes BD and CE to sides AC and AB are equal.

To prove: In ΔADB and ΔACE

Proof: ∠ADB=∠AEC=90 degree  (altitudes BD and CE to sides AC and AB)

BD=CE                         (Given altitudes are equal)

∠BAD=∠CAE            (Common angle )

ΔABD≅ΔACE           [by AAS congruence]

So AB=AC                   (by CPCT)

∴  triangle ABC is an isosceles triangle.

Step-by-step explanation: