ABC is a triangle. If points P, Q, R, S are on the sides of the triangle such that PQ || CA; QR || AB; RS || BC Show that AS = PB`
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Step-by-step explanation:
Given, in two Δ ABC and Δ PQR, AB/QR = BC/PR = CA/PQ
which shows that sides of one triangle are proportional to the side of the other triangle, then their corresponding angles are also equal, so by SSS similarity, triangles are similar.
i.e., Δ CAB ∼ Δ PQR
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