Question

ABC is a triangle in which AB = 5cm. BC = 7cm, CA = 9cm. If D.E and Fare the
midpoints of AB, BC and CA respectively, then the perimeter of the quadrilateral
DBEF is :​

Answer 1

Answer:

$AB =5cm \\ BC = 7cm \\ CA =9cm \\ Add \: it \: (5 + 7 + 9)cm = 21cm \\ \\ 180° - 21 = 159cm$