Question

Abc is a triangle in which ab=ac=4 cm and angle a =90 calculate the area of triangle abc.also find the length of perpendicular from a to bc.

Answer 1

ofrom given figure,
ABC is an right angled triangle
AD is the perpendicular drawn from point A to the BC
Area of traingle = 1/2 ×base × height
= 1/2× 4×4
= 2× 4
= 8
$cm ^{2}$


Now,by pythagoras theorem

$( ab)^{2} + (ac) ^{2} = ( bc) ^{2}$
(4)^{2} + (4)^{2}. = (bc)^{2}
16 + 16 = (bc)^{2}
32 =(bc)^{2}

4√2 = bc
perpendicular bisector bisect the segment into two equal parts
hence, AD = 4√2/2
AD = 2√2
therefore the length of the perpendicular is 2√2 cm.

Answer 2

Answer:

2√2 cm

check the attachment for the explanation