Question

ABC is a triangle in which Ab =AC and D is any point on BC prove that Ab^-Ad^ =Bd *Cd

Answer 1

Answer:

Step-by-step explanation:

In any triangle, the side opposite the greater angle is greater than the side opposite the smaller one. This is a consequence of the Law of Sines, and the fact that the sum of the angles of a triangle is π.

Now, in ΔABC, as AB>AC, ∠ACD>∠ABD.

Now, in ΔACD, the exterior angle ∠ADB=∠ACD+∠CAD (sum of interior opposite angles) > ∠ABD+∠CAD>∠ABD.

In ΔADB,∠ADB>∠ABD. Therefore AB>AD

Answer 2

Attachment.............⛄️
MARK BRAINLIEST