ABC IS A TRIANGLE IN WHICH AB=AC.D IS ANY POINT ON THE SIDE AB.THROUGH D,A LINE IS DRAWN PARALELL TO BC INTERSECTING AC AT E.
PROVE THAT AD=AE
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Given: AB=AC and D is a point on AB through D a line is drawn parallel to BC and meeting AC at E .
To prove: AD=AE
Using theorem the line drawn through the midpoint of one side of a triangle parallel to another side bisect the third side....……............………............(1)
E is the mid point of A.
AB=AC. (given)
1/2 AB=1/2 AC
AD=AE (they both are medians of AB and AC respectively)
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