Question

ABC is a triangle in which altitudes BE an CF to sides AC and AB are equal show (i) triangle ABE =∆ACF
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Answer 1

Answer:

Step-by-step explanation:   Proof, In triangle ABE & triangle ACF

                                                angle a = angle a( common )

                                                angle e = angle f = 90 degree ( BE and CF altitudes to side )

                                                AB = AC ( given )

Therefore, triangle ABE is congruent to triangle ACF ( by AAS rule)