Question

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal .show that

1 - AB=AC

Answer 1

given-BE=CF
proof-in triangle abe and a f c
BE=CF
ANGLE-A=ANGLE-A(COMMON)
ANGLE AFC= ANGLE-AEB
BY AAS CONGURENCE RULE BOTH TRIANGLE ARE CONGURENCE
BY CPCT
AB=AC

Answer 2

in tri. AFE & ACF
A = A (common)
be = cf
AFC = AEB (90°)
so, tri . AFE congruent tri. ACF ( ASA)
SO, AB = AC ( CPCT)