Question

ABC is a triangle in which angle B is equal to angle C And ray AX bisects the exterior angle d DAC if angle DAX is equal to 70 degree then find the angle ACB ​

Answer 1

Step-by-step explanation:

Angle A = 70 degree ( given )

Angle B = Angle C ( given )

as angle B= angle C

let both these angles be X

using angle sum property of

triangle

therefore 70+X+X =180

70+2x= 180

2x= 180-70

2x= 110

X=110/2

X=55 degree

therefore Angle C = Angle B = 55 degree

hence the proof

hope it helps

Answer 2

Answer:

Therefore triangle ABC=180°

a+b+c=180°

70+b+c=180°

b+c=180°-70°

b+c=110°

b+c=110°/2=55°

therefore ∆bc=55°

therefore a+b+c

70°+55°+55°=180°