Question

ABC is a triangle in which BC is produce to D, CA is produced to E angle DCA=30° and angle EAB =150°, calculate angle ABC​

Answer 1

Answer:

Correct option is

C

52  

∘

 

∠DCA= 108  

0

 

∠ACB=(180−108)=72degree

Since angle C on straight line BD is 180 degree.

∠EAB=124  

0

 

∠BAC=(180−124)=56  

0

degree

∠ABC=180−(∠BAC+∠BCA) Since sum of all angles of triangle is 180 degree

∠ABC=  180−(56+ 72)

∠ABC= 52  

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Step-by-step explanation: