Question

abc is a triangle in which d is a point on bc such that angle abd is 86 degree and angle acd 44 degree and ad is the bisector of angle bac find angle adc​

Answer 1

$\bigstar$ Question:

• ABC is a triangle in which D is a point on BC such that $\angle$ABD is 86° and $\angle$ACD is 44°. AD is the bisector of $\angle$BAC. Find $\angle$ADC.

$\bigstar$Given:

• $\angle$ABD = 86°
• $\angle$ ACD = 44°
• AD is the bisector of $\angle$BAC

$\bigstar$To find:

• The value of $\angle$ADC

$\bigstar$ Solution:

Let $\angle$BAD and $\angle$DAC be x.

(since $\angle$BAC is bisected, therefore both the angles are same)

Now, $\angle$ABC + $\angle$BCA + $\angle$BAC = 180°

( By Angle Sum Property Of A Triangle)

$\implies$ 86° + 44° + x + x = 180°

(Substituting their values)

$\implies$ 130° + 2x = 180°

$\implies$ 2x = 180° - 130°

$\implies$ 2x = 50°

$\implies$ x = 50°/2

$\implies$ x = 25°

Now, $\angle$ABC + $\angle$BAD = $\angle$ADC

( By exterior angle Property of a triangle)

$\implies$ 86° + x = $\angle$ADC

$\implies$ 86° + 25° = $\angle$ADC

$\implies$ $\angle$ADC = 111°

$\therefore$ $\angle$ADC = 111°

$\bigstar$ Answer:

$\therefore$ $\angle$ADC = 111°

Answer 2

Here Is your Answer

Answer is 110 Degree