ABC Is a triangle in which d is the mid point of ac. Bd is produced to e such that bd =de prove that ae is equal and parallel to bc
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In the given triangle ABC, BD is a median and BD = DE
In triangle BCD and Triangle EAD
CD = DA [BD is median]
BD = DE [given]
∠BDC = ∠EDA [vertically opposite angle]
By SAS, ΔBCD ≅ ΔEAD
CPCT, ∠BCD = ∠EAD
means alternate angles are equla then BC||AE
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