Question

ABC is a triangle In which DE B
is parallel to BC , find angle A

Answer 1

Answer:

DE//BC

ie., AD/DB=AE/EC. {by BT}

X/X+1=X+3/X+5

X(X+5)=(X+1)(X+3)

X^+5X=X^+3X+X+3

5X-3X-X-3=0

X-3=0

X=3

Step-by-step explanation: