ABC is a triangle in which < B = 900. Draw and label a sketch, then calculate the length of the third side of the triangle of side AB = 6m, BC = 8m.
(A) 14m
(B) 10m
(C) 12m
(D)
11m
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We have the length of 2 of the 3 sides of a right triangle: AB=6m, BC=8m , so we're looking for AC. Using the theorem Pythagoras gave us A²+B²=C².
6m²+8m²=C²
36m+64m=√100m =10m
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