Question

ABC is a triangle inscribed in a circle with center 0.if angle AOC =130°and angle BOC =150°.find angle AOB​

Answer 1

Answer:

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/_AOC = 130°

/_BOC = 150°

We know, /_AOB + /_BOC + /_AOC = 360° (Round angle)

/_AOB + 130° + 150° = 360°

/_AOB = 80°