Math, asked by navdhamehta, 9 months ago

ABC is a triangle. locate a point in the interior of ∆ABC which is equidistant from all the vertices of ∆ABC.​

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Answered by Anonymous
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ABC is a triangle. Locate a point in the interior of ABC which is equidistant from all the vertices of ABC. Ans. ... Hence O, the point of intersection of perpendicular bisectors of any two sides of ABC equidistant from its vertices.

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Answered by vanshika0932
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Answer:

ABC is a triangle. Locate a point in the interior of ABC which is equidistant from all the vertices of ABC. Ans. ... Hence O, the point of intersection of perpendicular bisectors of any two sides of ABC equidistant from its vertices.

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