ABC is a triangle. Locate a point in the interior of Angle ABC which is equidistant from all the vertices of Angle ABC. Answer fast
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Step-by-step explanation:
ABC is a triangle. Locate a point in the interior of ABC which is equidistant from all the vertices of ABC. Ans. ... Hence O, the point of intersection of perpendicular bisectors of any two sides of ABC equidistant from its vertices.
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Hence O,the point of intersection of perpendicular bisector of any two sides of ABC equidistant from it's vertices..
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