Question

ABC is a triangle. Perpendicular from C to AB meets the circumcircle of the triangle
at Q and perpendicular from B to CA meet the circumcircle at P.
Show that arc ARP = arc ASO, here R, S are points on AP, AQ.

Answer 1

Answer:

In Δ ABC, the perpendicular from vertices A and B on their opposite sides meet (when produced) the circumcircle of the triangle at points D and E respectively.

Answer 2

Answer:

In Δ ABC, the perpendicular from vertices A and B on their opposite sides meet (when produced) the circumcircle of the triangle at points D and E respectively.