Question

abc is a triangle.perpendicular from c to ab meets the circumference of the triangle at q and perpendicular from b to ca meet the circumference at p. show that arc arp=arc asq,here r,s are points on ap,aq

Answer 1

Answer:

Given: In ΔABC, the perpendiculars from vertices A and B on their opposite sides meet (when produced) the circumcircle of the triangle at points D and E respectively. To prove: Arc CD = Arc CE Construction: Join CE and CD

Proof.

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