Math, asked by siddharthmahalle43, 10 hours ago

ABC is a triangle, pq are point on AB and BC such that PQ is Parallel to BC, AP = 5cm, AB = 20 cm, AQ=7cm find AC​

Answers

Answered by shekhawatrajat855
0

ANSWER:

AC=28

STEP BY STEP EXPLATION:

In △ABC, PQ∥BC

first we have to find

PB=AB-AP

PB=20-5=15cm

AC=X

QC=Y

So, by proportionality theorem

AP/AB=AQ/QC

5/15=7/Y

1/3=7/Y

=>we do cross multiplication

Y=21

Now, for

AC=AQ+QC

AC=7+21

AC=28cm

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