Question

ABC is a triangle, PQ is the line segment intersecting AB in P and AC in Q such that?​

Answer 1

Answer:

u should ask ur question completely mate

Step-by-step explanation:

refer the attachment for the answer.....i hope this will help you ✌✌✌

Answer 2

hlo senior

hope tamanna di mil gayi hogi

Solution:-

Given : PQ is parallel to BC and PQ divides triangle ABC into two parts.To find : BP/AB

Proof : In Δ APQ Δ ABC,

∠ APQ = ∠ ABC (As PQ is parallel to BC)

∠ PAQ = ∠ BAC (Common angles)

⇒ Δ APQ ~ Δ ABC (BY AA similarity)

Therefore,

ar(Δ APQ)/ar(Δ ABC) = AP²/AB²

⇒ ar(Δ APQ)/2ar(Δ APQ) = AP²/AB²

⇒ 1/2 = AP²/AB²

⇒ AP/AB = 1/√2

⇒ (AB - BP)/AB = 1/√2

⇒ AB/AB - BP/AB = 1/√2

⇒ 1 - BP/AB = 1/√2

⇒ BP/AB = 1 - 1/√2

⇒ BP/AB = √2 - 1/√2 Answer