Question

ABC is a triangle right angled at B M is a point on BC prove that AB square + BC square is equal to AC square + b square​

Answer 1

Proved that AM² + BC² = AC² + BM².

Question :

ABC is a triangle right angled at B. M is a point on BC. Prove that AM² + BC²  is equal to AC² + BM².

To prove : AM² + BC² = AC² + BM²

Given :

ΔABC is right angled at B.

"M" is a point on BC.

From the figure,

Note : Figure is attached below    

Pythagoras theorem :                            

In a triangle, square the hypotenuse which is equal to the sum of square of the other two sides.

$(hypotenuse)^{2} = (one\ side)^2+(other \ side)^2$

Applying Pythagoras theorem in ΔABM :

In ΔABM,

AM² = AB² + BM²                                            

AB² = AM² - BM² -----> ( 1 )

Applying Pythagoras theorem in ΔABC :

In ΔABC,

AC² = AB² + BC²

AB² = AC² - BC² -----> ( 2 )

From equation ( 1 ) and ( 2 ), we get

AB² = AM² - BM² -----> ( 1 )

AB² = AC² - BC² -----> ( 2 )

AM² - BM² = AC² - BC²

AM² + BC² = BM² + AC²

Hence proved.    

               

To learn more...

1. In triangle abc angle B = 90 degree and M is a point on BC .prove that am square + bc square is equals to AC square + bm square

brainly.in/question/2146568

2. If ABC is a triangle right angled at B and m n are the midpoints of Ab and BC then 4 into n square + c m square equals to what

brainly.in/question/6479532

Answer 2

Answer:

Upar dekho yaar

Answered by Rudy